//program to get/display digits which are even in a number.

#include<stdio.h>

#include<conio.h>

#include<conio.h>

void main()

{

int n,rem;

printf("enter a number for 'n'\n");

scanf("%d",&n);

{

int n,rem;

printf("enter a number for 'n'\n");

scanf("%d",&n);

while(n!=0)

{

{

rem=n%10;

if(rem%2==0)

{

printf("%d",rem);

}

n=n/10;

}

getch();

}

--------------------------------------------------------------------------------------------------

**logics in mind:-**

>first we enter a number(for 'n').

->If we have number 123 then its even digits are 2 only. It means, first we have to get 3 then 2 and then 1 to check all digits.

->For this,

->we have to divide by 10 to get last digit as remainder.

->we divide that 'remainder' by 2 to get remainder.If 'remainder' is 0 then we understand that the digit is even and if not then that is not.

->Then we display that.

-> to get second digit, we get first 12 and for this , we use 123/10.It is done to get integer part only.

->We repeat this until the value reaches 0. We use loop for this as shown above in the code.

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