//program to get/display digits which are odd positioned in a number.

#include<stdio.h>

#include<conio.h>

#include<conio.h>

void main()

{

int n,rem,count=0;

printf("enter a number for 'n'\n");

scanf("%d",&n);

{

int n,rem,count=0;

printf("enter a number for 'n'\n");

scanf("%d",&n);

while(n!=0)

{

{

rem=n%10;

count++;

if(count%2!=0)

{

printf("%d",rem);

}

n=n/10;

}

getch();

}

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**logics in mind:-**

>first we enter a number(for 'n').

->If we have number 123 then its odd positioned digits are 1 and 3(from both side). It means, first we have to get 3 then 2 and then 1 to check all digits.

->For this,

->we have to divide by 10 to get last digit.

->we also use 'count' with initial value '0' to to know position of digits.

->we divide that count by 2 to get remainder.If count is not equal to 2 then we understand that the digit is in odd position and if not then that is not.

->Then we display that.

-> to get second digit, we get first 12 and for this , we use 123/10.It is done to get integer part only.

->We repeat this until the value reaches 0. We use loop for this as shown above in the code.