//program to print/display all characters from a to z.
#include<stdio.h>
#include<conio.h>
void main()
{
int k=97;
while(k<=122)
{
printf("%c,",k);
k++;
}
getch();
}
logic applied:
1)You should know ascii value of all characters then apply that in loop.
ascii value of 'a' is 97 and z is 122.
so apply this value in a loop and print as a character(%c).
or
2)You can use all characters stored in a string and then display one by one.
e.g.
int j;
char string[]="abcdefghijklmnopqrstuvwxyz";
for(j=0;string[j]!='\0';j++)
{
printf("%c\n",string[j]);
}
put this code in side void main and execute them . you get output.
#include<stdio.h>
#include<conio.h>
void main()
{
int k=97;
while(k<=122)
{
printf("%c,",k);
k++;
}
getch();
}
logic applied:
1)You should know ascii value of all characters then apply that in loop.
ascii value of 'a' is 97 and z is 122.
so apply this value in a loop and print as a character(%c).
or
2)You can use all characters stored in a string and then display one by one.
e.g.
int j;
char string[]="abcdefghijklmnopqrstuvwxyz";
for(j=0;string[j]!='\0';j++)
{
printf("%c\n",string[j]);
}
put this code in side void main and execute them . you get output.
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