hseb solution:program to know a number is even or odd

First part:
Algorithm to know a number is even or odd
step 1:read/input a number 'x'
step 2:Let y= remainder obtained after dividing x by 2
step 3:If y=0 then
          display it is an even
         else
         display it is an odd
step 4:stop

second part:-

Flowchart:-

//'C' program to know a number is even or odd
#include<stdio.h>
#include<conio.h>
void main()
{
int x;
printf("enter a number\n");
scanf("%d",&x);
if(x%2==0)
{
printf("it is an even number");
}
else
{
printf("it is an odd number\n");
}
getch();
}

program to enter some elements and display that in opposite order.

//array program to input elements and to display them in reverse order
  #include<stdio.h>
  #include<conio.h>
  void main()
  {
  clrscr();
  int arr[100];      // array declaration with maximum size 100
  int size;     // size to be used to input elements
  int i;            //variable declaration
  printf("enter size of elements \n");//displays message
  scanf("%d",&size);                  //gets input for array size
  for(i=0;i<size;i++)
   {                            //loop execution
     printf("enter elements\n");//displays message
     scanf("%d",&arr[i]);      //gets input for  array entered by user

   }
   printf("elements, in reverse order, are\n");
   for(i=size-1;i>=0;i--)
   {
   printf("%d\n",arr[i]);       // displays  elements
   }
   getch();

   }
--------------------------------------------------
logics:-

1)declare an array of  partiular size.

2)input elements for this using loop.

3)to display, use loop from given size-1 to 0 location (look above)

that's all

more, u can understand from side by description given in program

-------------------------

screen shot

output:

Write a program to get given pattern

/*WAP to get following
                                  * * * * * 
                        * * * * *
                   * * * * * 
             * * * * *

*/

#include<stdio.h>

#include<conio.h>

void main()

{

clrscr();

int i,j,k;

for(i=1;i<=5;i++)      //for number of rows. there are five rows so loop moves fives times

  {

    for(k=8;k>=i;k--)

      {

      printf(" ");   // this part is for space. every time , on display, it decreases space.

      }

    for(j=1;j<=4;j++) //it displays star five times.It displays in columns

      {

 printf("* ");

      }

    printf("\n"););

}

getch();

}

---------------------------

logic in mind:-

----------

it has three parts:

first is number of rows

second part is number of columns

third part decreasing space on each display.

1)fist loop is used for number of rows

2) the inner loop is for space to display

3)the inner most is for star display every time.

Program's screen:-

program's output:

Note:-

From here onward, we are writing program using return and int main().

so using return, it looks like.

#include <stdio.h>
#include<conio.h>
int main()
{
  int i,j,k;
for(i=1;i<=5;i++)      //for number of rows. there are five rows so loop moves fives times
  {
    for(k=8;k>=i;k--)
      {
      printf(" ");   // this part is for space. every time , on display, it decreases space.
      }
    for(j=1;j<=4;j++) //it displays star five times.It displays in columns
      {
 printf("* ");
      }
    printf("\n");
}
   getch();
  return 0;
}

---------------------------------------------------

read me:-

nothing you have to do here. Just put int main() in the beginning and return 0 at the end

wap to display star pattern

/*program to display following

* * * * *

    * * * * *

* * * * *

         * * * * *

             * * * * *

*/

#include<stdio.h>

#include<conio.h>

void main()

{

clrscr();

int i,j,k;

for(i=5;i>=1;i--)      //for number of rows. there are five rows so loop moves fives times

  {

    for(k=i;k<=7;k++)

      {

      printf(" ");   // this part is for space. every time , on display, it increases space.

      }

    for(j=1;j<=5;j++) //it displays star five times.It displays in columns

      {

printf("* ");

      }

    printf("\n");

}

getch();

}

---------------------------

logic in mind:-

----------

it has three parts:

first is number of rows

second part is number of columns

third part increasing space on each display.

1)fist loop is used for number of rows

2) the inner loop is for space to display

3)the inner most is for star display everytime.

------------------------------------------------------

program screenshot

output is

WEAP to display following star pattern

/*program to display following

* * * * *
* * * * *
* * * * *
* * * * *
* * * * *

*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j;
for(i=1;i<=5;i++)      //for number of rows. there are five rows so loop moves fives times
  {
    for(j=1;j<=5;j++) //it displays star five times.It displays in columns
      {
printf("* ");
      }
    printf("\n");
}
getch();
}

------------------------------------
logic in mind:-
1)we have to display five rows and five columns.
2) we have used outer loop five times.
3)and inner loop five times.
-------------------------------
 program 's screenshot

output

write a program to display plus pattern

/*to display following
  +
               +
               +
               +
   + + + + + + + + +
              +
              +
              +
              +
              +
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='+';
int i,j,k=0,k1;
for(i=4;i>=0;i--)
{
  for(k1=-3;k1<=5;k1++)
     {
       printf(" ");
     }
  for(j=1;j<=1;j++)
    {
      printf("%c",a);
    }
  printf("\n");
}
for(i=1;i<=9;i++)
{
for(k1=5;k1<=5;k1++)
     {
       printf(" ");
     }
printf("+");
}
for(i=4;i>=0;i--)
{
  for(k1=-3;k1<=5;k1++)
     {
       printf(" ");
     }
  for(j=1;j<=1;j++)
    {
      printf("%c",a);
    }
  printf("\n");
}
getch();

}

-------------------

logic in mind:-
1)for this display, we have three parts.
      first part is upper 
      second part is horizontal
      third part is vertical form(look circled part)
2) First we display upper part using three loops.
          outer loop is for number of rows
           inner is for space(constant)
          inner most is for display
3) similarly, for second part we have done. ----------------------
program's screenshot:-

----------------------------
program's output:-

WAP to get following alphabetical pattern

/*WAP to get following

ABCDE
ABCD
ABC
AB
A
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=4;i>=0;i--)
{
  for(j=0;j<=i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");

}
getch();
}
-----------------
logic in mind
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so. 
for more: look down.
--------------
program screenshot:-

program output:-

to display letters' pattern

/*to display following
A
AB
ABC
ABCD
ABCDE
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=1;i<=5;i++)
{
  for(j=0;j<i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");

}
getch();
}
-------------------
logic in mind:-
-------------
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so.
for more: look down.
program screenshot:-

program output:-

to display letters' pattern

/*to display following
A
AB
ABC
ABCD
ABCDE
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=1;i<=5;i++)
{
  for(j=0;j<i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");
  //a++;
}
getch();
}
-------------------
logic in mind:-
-------------
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so.
for more: look down.
program screenshot:-

program output:-

to display letters' pattern

/*to display following
A
AB
ABC
ABCD
ABCDE
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
char a='A';
int i,j,k=0;
for(i=1;i<=5;i++)
{
  for(j=0;j<i;j++)
    {
      printf("%c",a+j);
    }
  printf("\n");

}
getch();
}
-------------------
logic in mind:-
-------------
1) we have to display different characters in different rows and columns.
2)there are five rows and columns. The column is decreased in each display.
3)for this, we have used first loop for different rows.
4)second loop is for display. It fetches value from first loop and displays different character.
5)second loop is taken from value 0.because,  in each display, the character changes so.
for more: look down.
program screenshot:-

program output:-

Write a program to get following numeric pattern.

/*Write a program to get following numeric pattern.
0
01
012
0123                                                                                                                    
012
01
0
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j;
for(i=0;i<=3;i++)
{
 for(j=0;j<=i;j++)
   {
      printf("%d",j);

   }
      printf("\n");
}
for(i=2;i>=0;i--)
{
 for(j=0;j<=i;j++)
   {
      printf("%d",j);

   }
      printf("\n");
}
getch();
}

-------------------------------------------------

logic in mind:-

1) we have to display given pattern.It has two parts

      first part is:upper part .i..e

        0

       01
       012
        0123   

  and second part is

     012
     01
     0
2)for first part, like shown below, we use loop to fetch value from outer loop and displaying from inner loop
3)for second part, we use once again loop with one less value. We fetch that and display from inner loop
just look down.

program's screenshot:

----------------------------

output screen:

program to display following star pattern.

 /*program to display following star pattern.
         * * * * * *
           * * * *
            * * *
             * *
              *
             *
            * *                                                                                                           
           * * *
         * * * *
       * * * * * 
*/
#include<stdio.h>
#include<conio.h>
void main(void)
{
clrscr();
int i,j,k,sp=1;
//printf("for upper part");
 for(i=1;i<=5;i++)
   {
for(k=sp;k<=i;k++)
  {
    printf(" ");

     }
    for(j=5;j>=i;j-- )
      {
printf(" *");
    }
    printf("\n");
}
 //printf("for lower part");

 sp=5;
 for(i=1;i<=5;i++)
   {
for(k=sp;k>=i;k=k-1)
  {   printf(" ");

     }
    for(j=1;j<=i;j++)
      {
      printf(" *");
    }
    printf("\n");
}
getch();

}
-------------------------------
logic in mind:-
---------------------------------
1)First loop is for number of rows.
2)like other programs, we display first upper part. 
       For this, we, first, display space (second loop)and then star(third loop.
3)For second part, we display first space(look diagram) using loop then we display star.
------------------------------------------------------------------------------------------------------------------------------
program's screenshot:-

programs output:-

program to display following star pattern.

/*program to display following star pattern.
              *
             *     *                                                                                                  
             *            *
             *                   *
             * * * * * * * * *                
             * *
             *     *
             *         *
             *             *
             *                  *
             *  * * * * * * * *
             *
             *
             *
*/
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,k,m,sp=7;
//printf("first upper part");
for(i=1;i<=5;i++)
 {

for(m=i;m<= i;m++)
{
printf("*");
}
 for(m=1;m<i;m++)
 {
 printf("  ");
 }
   for(m=i;m<=i;m++)
    {
      if(m==1)
      printf(" ");
      else
      printf("*");

    }

 printf("\n");
 }
 for(i=1;i<=10;i++)
 {
 printf("*");
 }
//printf("second lower part");
for(i=1;i<=5;i++)
 {

for(m=i;m<= i;m++)
{
printf("*");
}
 for(m=1;m<i;m++)
 {
 printf("  ");
 }
   for(m=i;m<=i;m++)
    {
      if(m==1)
      printf(" ");
      else
      printf("*");

    }

 printf("\n");
 }
 for(i=1;i<=10;i++)
 {
 printf("*");
 }
  for(i=1;i<=5;i++)
 {
 printf("*\n");
 }
 getch();
 }
-------------------------------
logics in mind:-
-------------------------------
1)it contains three parts:
        first part is upper right angled triangle
        second part is lower right angled triangle
        third part is tail
If we combine them then we get that.
2) To get upper part we have already done. follow the link
            https://practicingclanguage.blogspot.com/2016/09/program-to-display-following-star_21.html
3)To get lower part, follow the link
        https://practicingclanguage.blogspot.com/2016/09/program-to-display-following-star_21.html
4) to get left part, use loop few number of times. It's done
---------------------------------------------------------------------------------
Follow following shot for more.

program screenshot:-

output screen shot:-