program to get sum of given series with................nth terms.

//program to get sum of x+ x²/2+x³/3+x⁴/4+.............................nth terms.
#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()
{
  float i,n,x,m=1,sum=0;

   printf("enter  positive number for 'n'\n");
  scanf("%f",&n);

printf("enter value for 'x'\n");

scanf("%f",&x);

  for(i=1;i<=n;i++)
    {               

          sum=sum+(pow(x,m)/i);

           m=m+1;

     }

  printf("the sum=%f",sum);

getch();
}

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logics in mind:
->enter a number for range for which you want to get sum, say 'n'.

->let a variable 'sum' with initial value '0'

->here we also need value for 'x' so let's input that

->we get sum using formula sum=sum+(pow(x,m)/i); because in terms x+ x²/2+x³/3+x⁴/4+..............  ,

    ->we have two components namely numerator and denominator. Let's look at numerator;they are

           x¹,x²,x³,x⁴.....it can be formulated as pow(x,m) .  .here the power (m) goes on increasing.
   ->similarly for denominator, it is simply 1,2,3,4.... so it can be used from loop (variable i).

->we find sum inside loop

->at last we display the final sum.

   here 'pow' means finding power. it exists inside math.h