program to display given numeric pattern

//program to display following numeric pattern.
//               1 2 3 4 5
//               6 7 8 9 10
//               11 12 13 14 15
#include<stdio.h>
#include<conio.h>
void main(void)
{
clrscr();
int i,j,k=0;
 for(i=1;i<=3;i++)
   {
   for(j=1;j<=5;j++)
       {
       printf(" %d",j+k);
      }
    printf("\n");
k=k+5;}
getch();
}
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logic in mind:-
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1)we have to display 1 2 3 4 5 then different numbers in second row..
2)we can see there are three rows so we use first loop(outer) with three execution times. And there are         5 columns so we use one another loop(five times execution) for columns(inner).
3) since the pattern is like
        1+0   2+0   3+0  4+0  5+0
       1+5   2+5   3+5   4+5  5+5
and so on.
4) For this, We have used nested loop as shown above and one variable named k with initial value '0'.
5)For each value of outer loop(value of 'i'), the inner loop executes 5 times. And it goes to display numbers.
 while displaying, it adds both numbers (j and k)and displays on screen.
6)In second display the value of k is increased by 5 as shown above.
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program's screenshot
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output is:-
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