//armstrong numbers lying in given range 0 and 1000

//we are taking numbers with three digits

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

clrscr();

int i=1,rem,k,sum=0;

while(i<=1000)

{

k=i;

sum=0;

while(k!=0)

{

rem=k%10;

sum=sum+pow(rem,3);

k=k/10;

}

if(sum==i)

{

printf("%d\n",i);

}

sum=0;

i++;

}

getch();

}

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-------------------

->we have to display Armstrong numbers in given range 0 and 1000.Armstrong can be for 3/4 digits numbers.

Here we taking 3 digits only.

//we are taking numbers with three digits

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

clrscr();

int i=1,rem,k,sum=0;

while(i<=1000)

{

k=i;

sum=0;

while(k!=0)

{

rem=k%10;

sum=sum+pow(rem,3);

k=k/10;

}

if(sum==i)

{

printf("%d\n",i);

}

sum=0;

i++;

}

getch();

}

-----------------------------------------------------------------------------------------------------------------------------------------------------------

**logics in mind:-**-------------------

->we have to display Armstrong numbers in given range 0 and 1000.Armstrong can be for 3/4 digits numbers.

Here we taking 3 digits only.

->First we take first number (k) then we apply following method

->For this,

->we have to divide by 10 to get last digit as remainder

->we find its cube and then go for sum

-> to get second digit, we get first 12 and for this , we use 123/10.It is done to get integer part only.

->then we compare the number 'i' with that sum. If they are same then we display that.

->We repeat this until the value reaches 0 and for all numbers and individually. We use loop for this as shown above in the code.

->as the first number is checked, we , once again, assign value '0' to sum to check next value.And this goes on.

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